Hey lads! Somebody asked me earlier for a screenshot of my setup. I thought it would be a little too easy if I just gave him the link, so I decided to make a dead-simple CTF.
However, a lot of people haven’t actually found the answer? So I present the challenge to you. Can you find the URL?
https://pry0.cc/web/CanYouFindMe/
Good luck!
That was fun. 
!
LOL. Nice riddle! 
How to get it:
Open the site and take a look at the HTML-Code:
<html>
<head>
<script src="load.js"></script>
</head>
<body>
</body>
<h1> Hello! </h1>
<p> Can you find <a href="#Nice-try-you-sucker">me?</a> ... </p>
</html>
After falling for the awesome trap, you’ll instantly recognize the loader.js file, which is in fact never executed. The file contains the following code:
function load() {
console.log("V2hhdCB5b3UgYXJlIGxvb2tpbmcgZm9yPw0KDQphSFIwY0hNNkx5OXBiV2QxY2k1amIyMHZZUzlSVlVOa1dRPT0=");
}
With a little sense for obfuscation, it should be clear that we are presented with a Base64 encoded string, which decodes to the following:
What you are looking for?
aHR0cHM6Ly9pbWd1ci5jb20vYS9RVUNkWQ==
This contains another Base64 string:
aHR0cHM6Ly9pbWd1ci5jb20vYS9RVUNkWQ==
=> Which finally results to the picture:
https://imgur.com/a/QUCdY
Wanted to go to sleep, saw the riddle, had a little fun before bed .
There it is. The killer setup. As promised! 
Couldn’t help but wonder :
Do you think there exists a base64 encoded string that infinitely decodes to another valid base64 encoded string ?
In which case you could turn your ctf into a massive rickrolling 
The problem in itself doesn’t seem particularly useful but hey, maybe some crazy mathematician published something about it
Nice one. Thanks for giving me a laugh. Cheers.
What is up with this community and Base64? I really don’t get it why it is so special. Can someone explain?
-Phoenix750
Its cool. It maintains everything and is borderline readable. Plus its easily recognisable.
Even google uses it in the email source code. It’s simple but awesome.
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